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Two point charges +1 nC and 4 nC are 1 m apart in air. Find the positions along the line joining the two charges at which resultant potential is zero. |
Answer» Solution : At A charge is `1 xx 10^(-9) C` At B charge is `- 4 xx 10^(-9) C ` Now at P RESULTANT potential is zero. ` therefore (1)/(4 r epsi_0) [ (1 xx 10^(-9))/(x ) - (4 xx 10^(-9))/(1 - x) ] = 0` `([(1 xx x) - 4(x)] xx 10^(-9))/(x(1 -x )) = 0` ` + 1 - x -4x = 0` ` 1 = 5x` `x= 1/5 = 0.2m` |
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