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Two point charges 10 muC and -10 muC are separated by a distance of 40 cm in air. Calculate the electrostatic potential energy of the system, assuming the zero of the potential energy to be at infinity. |
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Answer» Solution :Here `q_1 = + 10 MUC=10 xx 10^(-6)C, q_2 = 10 muC= - 10 xx 10^(6) C and R = 40 cm= 0.4 m` `:.` POTENTIAL energy of the system `u = (q_1 q_2)/(4pi epsi_0r) = (9 xx 10^9 xx (10 xx 10^(-6)) xx (-10 xx 10^(-6)))/0.4 = -2.25 J`. |
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