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Two point charges+ 4 muC and -2 muC are separated by a distance of 1 m in air. Calculate at what point on the line joining the two charges is the electric potential zero. |
Answer» SOLUTION :Here `q_1= 4 mu C , q_2 = -2 muC ` and distance between them r = 1 m  As shown in figure net electric potential is zero at point `C_1` situated between the two charges and at point `C_2` situated on extension of line JOINING the two charges. If distance of point `C_1 or C_2` from `q_1` be X, then For point `C_1 : V_1 + V_2= 1/(4pi epsi_0) [q_1/x+ q_2/((r - x))] = 0 rArr (4muC)/x + ((-2 muC))/((1-x)) = 0 rArrx = 2/3 m` Similarly for point `C_2 : q_1/x + 1/((x -r)) = 0 rArr (4 muC)/x + ((-2 muC))/((x + 1)) = 0 rArr x = 2M` |
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