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Two point charges 4 muC and 9 muC are separated by 30 cm. Find the point where the strength of the field is zero. |
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Answer» Solution :The distance x of the null POINT `4 mu C` charge and between the two charge is `4/(x^2) = 9/((30 - x)^2) cdot (or) x = 30/(sqrt(9/4) + 1)= (30 xx 2)/(5) = 12 cm`. |
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