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Two point charges 4mu C and 9muC are separated by 30cm. Find the point where the strength of the field is zero. |
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Answer» Solution :The distance x of the null POINT `4mu C` CHARGE and between the two charge is `(4)/(x^(2)) = (9)/((30-x)^(2)) (or) x = (30)/(sqrt((9)/(4))+1)= (30 xx 2)/(5) = 12cm` |
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