Saved Bookmarks
| 1. |
Two point charges +4muCand +1muCare separated by a distance of 2 m in air. Find the point on the line joining the two charges at which the net electric field of the system is zero. |
|
Answer» Solution :Let charges ` q_1 =+4 muC and q_2 =+1muC ` be placed at points. A and B respectivelyseparated by a distance AB = 2 m. Let electric field ` oversetto E ` be zero at a point C situated at a distance x from A or a distance (2-x) from B as shown in Thus, `oversetto (E_A) +oversetto (E_B) =0 or |oversetto (E_A)| =|oversetto (E_B)| ` `RARR "" (1)/(4piin _0).(q_1)/(x_2)=(1)/(4 pi in _0) .(q_2)/((2-x)^(2)) rArr (x)/((2-x)) =SQRT((q_1)/(q_2)) = sqrt((4MUC )/(1 muC)) = 2 ` `rArr "" x= (4)/(3) m ` ` (##U_LIK_SP_PHY_XII_C01_E09_009_S01.png" width="80%"> |
|