Saved Bookmarks
| 1. |
Two point charges are separated by some distance , repel each other with a force F. What will be the force if distance between them is halved ? |
|
Answer» SOLUTION :`F=1/(4piepsilon_0)(q_1q_2)/r^2` When `r=r/2` `F.=1/(4piepsilon_0) (q_1q_2)/((r/2)^2)=41/(4piepsilon_0) (q_1q_2)/r^2=4F` NEW FORCE F.=4F |
|