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Two point charges are separated by some distance , repel each other with a force F. What will be the force if distance between them is halved ?

Answer»

SOLUTION :`F=1/(4piepsilon_0)(q_1q_2)/r^2`
When `r=r/2`
`F.=1/(4piepsilon_0) (q_1q_2)/((r/2)^2)=41/(4piepsilon_0) (q_1q_2)/r^2=4F`
NEW FORCE F.=4F


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