Saved Bookmarks
| 1. |
Two point charges are seperated by a distance r such that a medium of dielectricconstant K is occupied by a length x Now find the coulomb force between those stationary charges. |
|
Answer» Solution :In this CASE we removethe dielectricand its effective equivalent distance in free space can be taken as `sqrt(K)X` Now the force between the point charges is `F=(1)/(4pi in_(0)) (q_(1)q_(2))/({(R-x)+sqrt(K)x}^(2))` If K = 4 and`x=r//2` `F=(1)/(4pi in_(0)) (4q_(1)q_(2))/( 9R^(2)) =(4)/(9) (1)/(4pi in_(0)) (q_(1)q_(2))/(r^(2))` `F=(4)/(9)F_(0)` where `F_(0)=(1)/(4pi in_(0))(q_(1)q_(2))/(r^(2))` which is the force between the charges if they are separatedby r in vacuum. |
|