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Two point charges of 6 nC and 12 nC are placed at the corners of B and C of an equilateral triangle ABC of side 0.03 m . Calculate the magnitude of the resultant electric intensity at the vertex A of triangle. |
Answer» Solution : `E=(1)/(4piepsilon_(0))(q)/(d^(2))or(9xx10^(9))(q)/(d^(2))` `E=6xx10^(4)NC^(-1)` and `E_(2)=12XX10^(4)NC^(-1)` `E=sqrt(E_(1)^(2)+E_(2)^(2)+2E_(1)E_(2)costheta)`, `theta=60^(@)` `E=15.87xx10^(4)NC^(-1)` or `6sqrt(7)xx10^(4)NC^(-1)` |
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