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Two point charges of magnitude + q and - q are placed at (-(d)/(2),0,0) and ((d)/(2),0,0) . respectively. Find the equation of the equipotential surface where the potential is zero. |
Answer» Solution :Let the REQUIRED plane lies at a distance x from the origin as shown in figure.  POTENTIAL at POINT P `(kp)/([(x+(d)/(2))^(2)+H^(2)]^(1//20))-(kq)/([(x-(d)/(2))^(2)+h^(2)]^(1//2))=0` `:. (1)/([(x+(d)/(2))^(2)+h^(2)]^(1//2))=(1)/([(x-(d)/(2))^(2)+h^(2)]^(1//2))` `:. (x+(d)/(2))^(2)+h^(2)=(x+(d)/(2))^(2)+h^(2)` `:. x^(2)-xd+(d^(2))/(4)=x^(2)+xd+(d^(2))/(4)` `:. 0 =2xd` `:. x=0` It is the required equation of the potential for EQUIPOTENTIAL surface at x = 0 means yz plane. |
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