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Two point charges of values -20 esu and +20 esu are placed on the x-axis at x = -10cm and x = +10cm respectively. Calculate (iii) Find the work done in carrying a positive charge of value +6 esu from P to Q along a straight the joining them. |
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Answer» Solution :TWO CHARGES + 20 esu and -20 esu are placed at A and B respectively. (iii) WORK done to bring a positivecharge of value 6 esu from P to Q, `W = 6(V_(Q) - V_(P)) = 6 XX 4/3 = 8 erg`. |
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