InterviewSolution
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InterviewSolution
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Two point charges, q_1 = 10 xx 10^(-8) C and q_2= -2 xx 10^(-8) C, are separated by a distance of 60 cm in air. Also calculate the electrostatic potential energy of the system. |
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Answer» Solution :Here `q_1= + 10 XX 10^(-8)C and q_2 = - 2 xx 10^(-8) C` and distance between them r = 60 CM = 0.6m Electrostatic POTENTIAL energy of the system `u = (q_1q_2)/(4pi epsi_0.r) = ((10 xx 10^(-8)) xx (-2 xx 10^(-8)) xx 9 xx 10^(9))/0.6 = -3 xx 10^(-5)J` |
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