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Two point charges q_(1) and q_(2) (like) are seperated by a distancer and fixed. Locatethe point on the line joining those charges where resultantor net field is zero. |
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Answer» Solution :Let P BETHE null point where `barE_("net") =0` ` rArr barE_(1)+barE_(2) =0` (due to thosecharges) or `barE_(1) = -barE_(2) and E_(1)=E_(2)` `rArr (1)/(4PI in_(0)) (q_(1))/(x^(2)) =(1)/( 4pi in_(0)) (q_(2))/((r-x)^(2)) or (q_(1))/(x^(2)) =(q_(2))/( (r-x)^(2))` From this we get x. If the chargesare like, the neutral point will be between the charges, ifthe chargesare unlike the neutralpoint will be outsidethe charge on the line joining them.  `:.` In this case `(q_(1))/(x^(2)) =(q_(2))/((r+x)^(2))`. |
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