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Two point charges q_A= 3muC and q_(B) = -3muC are located 20 cm apart in vacuum. a. What is the electric field at the midpoint O of the line AB joining the two charges? b. If a negative test charge of magnitude 1.5.xx 10^(-9) C is placed at this point, what is the force experienced by the test charge? |
Answer» Solution : a. `E=E_(1)+E_(2)` `E_(t)=(9 xx 10^(9) q_(A))/((AO)^(2)) =(9 xx 10^(9) xx 3 xx 10^(-5))/((10 xx 10^(-2))^(2)) =27 xx 10^(5) "N/C ALONG OB"` `E_(2)=(9 xx 10^(9) q_(B))/((BO)^(2))=(9 xx 10^(9) xx 3 xx 10^(-6))/((10 xx 10^(-2))^(2)) =27 xx 10^(5)" N/C along OA"` `E=E_(1)+E_(2) =54 xx 10^(5) NC^(-1)" along OB"` b. `F_(1)=9 xx 10^(9) (q_(A)q)/((OA)^(2)) =(9 xx 10^(9) xx 3xx 10^(-6) xx 1.5 xx 10^(-9))/((10 xx 10^(-2))^(2)) =40.5 xx 10^(-4)N` `F_(2)=(9 xx 10^(9) xx 3 xx 10^(-6) xx 1.5 xx 10^(-9))/((10 xx 10^(-2))^(2)) =40.5 xx 10^(-6)N` `F=F_(1)+F_(2)=81 xx 10^(-4)" N along OA"` |
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