1.

Two point like charges having magnitude =16 muCand -9muC are separated by a distance 10 cm in air. The resultant electric field will bt zero at distance......from -9muC charge.

Answer»

30 cm
20 cm
10 cm
40 cm

Solution :Here `|vecE_(1)| =|vecE_(2)|`
`therefore q_(1)/(x+10)^(2) =q_(2)/x^(2)`
`therefore q_(1)/q_(2) =((x+10)/x)^(2)`
`therefore 16/9 =((x+10)/x)^(2)`
`therefore 4/3 =(x+10)/x`
`therefore 4x = 3x + 30, therefore x = 30 cm`


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