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Two point masses each equal to 1 kg attract one another with a force of `10^(-9)` kg-wt. the distance between the two point masses is approximately `(G = 6.6 xx 10^(-11) "MKS units")`A. 8 cmB. 0.8 cmC. 80 cmD. 0.08 cm |
Answer» Correct Answer - A `F=(Gm_(1)m_(2))/(r^(2))` `:. r=sqrt((Gm_(1)m_(2))/(F))=sqrt((6.67xx10^(-11)xx1xx1)/(9.8xx10^(-9)))=0.082 "m" = 8.2 " cm"`. |
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