1.

Two point masses each equal to 1 kg attract one another with a force of `9.8×10^(-9)` kg-wt. the distance between the two point masses is approximately `(G = 6.6 xx 10^(-11) "MKS units")`A. 8.2 cmB. 0.8 cmC. 82 cmD. 0.08 cm

Answer» Correct Answer - A
`F=(Gm_(1)m_(2))/(r^(2)`
`therefore r=sqrt(Gm_(1)m_(2))/(F)=sqrt(6.67xx10^(-11)xx1xx1)/(9.8xx10^(-9))`
`=0.082 m =8.2 cm`


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