Two point source S_(1) and S_(2) separated by a distanc 10 mu m in phase. A circular wire of radius 40mu m is placed around the sources as shown in figure, then (O is the centre of the circle and OS_(2) = OS_(2))

Two point source S_(1) and S_(2) separated by a distanc 10 mu m in pha

1.	Two point source S_(1) and S_(2) separated by a distanc 10 mu m in phase. A circular wire of radius 40mu m is placed around the sources as shown in figure, then (O is the centre of the circle and OS_(2) = OS_(2))
Answer» point A and B are dark and points C and D are BRIGHT point A and B are bright and point C and D are dark point A and C are dark and points B and D are bright point A and C are bright and points B and D are dark Solution :Path difference at point B, `Delta x_(B) = S_(1)B - S_(2)B = 0` and at point D, `Deltax_(D) = S_(1)D - S_(2)D = 0` Phase difference, `phi = (2pi)/(lamda) xx (0) = 0` So, intensity at points B and D `I = I_("max") cos^(2) (phi//2) = I_("max")` So, points B and D are bright. Phase difference at point A, `Deltax_(A) = 35mu m [40-5]` But, FIGURE shows `Deltax_(A) = Delta X_(C )` is maximum for given circle. When path difference is maximum, intensity will be MINIMUM. So, point A and C are dark.

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Two point source S_(1) and S_(2) separated by a distanc 10 mu m in phase. A circular wire of radius 40mu m is placed around the sources as shown in figure, then (O is the centre of the circle and OS_(2) = OS_(2))

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