1.

Two point white dots are 1 mm apart on a black paper. They are viewed by eye of pupil diameter 3 mm. Approximately, what is the maximum distance at which these dots can be resolved by the eye ? [Take wavelength of light = 500 nm]

Answer»

6 m
3 m
5 m
1 m

Solution :
`alpha_(MIN)=(1.22lambda)/(D)=(d_m)/(R)`
`thereforeR=(Dxxd_m)/(1.22lambda)`
`thereforeR=(3xx10^(-3)xx1xx10^(-3))/(1.22xx500xx10^(-9))`
`thereforeR=4.918` m
`THEREFORE` R=5 m


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