1.

Two pointa white dots are 1 mm apart on a black paper.They are viewed by eye of pupil of diameter 3 mm. Nearly what is max. Distance at which these dots can be resolved by eye?(lambda of light is 500 mm)

Answer»

3 m
6 m
1 m
5 m

Solution :`d THETA = (1.22 lambda)/(D) = (d)/(R)`
Then R = 4.92 m.


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