InterviewSolution
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InterviewSolution
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Two pointcharges q_(1) and q_(2) of magnitude + 10^(-8) c and -10^(-8) crespectively are placed 0.1 m apart calculate the electricfields at points a, b and c |
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Answer» Solution :The electricflield vector `E_(1A)` at a due to the positive charge `q_(1)`point towards the right and has a magnitude `E_(1A)=(9xx10^(9)Nm^(2)C^(2)XX(10^(-8)C))/(0.05 m)^(2)=3.6 xx10^(4) NC^(-1)`the electirc field vectors`E_(2A)`at a due to the negative charge `q_(2)` pointsof the total electric field `E_(A)`at A is `E_(A)` is directedtowards the right the electricfieldvector `E_(1B)`at B due to thepositive charge `q_(1)` pointstowards the leftand has a manitude the magnitude of the total electricfieldat Bis `E_(B)` is directed towards the left The magnitude of each electricfieldvectorat pointc due to charge `q_(1)` and `q_(2)`is `E_( c)=E_(1c)` cos `(PI)/(3)+E_(2c)` cos `(pi)/(3)=9xx10^(3) Nc^(-1)` `E_(c )` points towards the right |
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