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Two polarising sheets are arranged with their axes parallel so that the intensity of transmitted polarized light is maximum. Through what angle must the sheet be rotated so that the intensity of transmitted light drops to1/3of the maximum intensity? |
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Answer» SOLUTION :By LAW of Malus`I=I_(0)cos^(2) theta`But`I=(I_(0))/3 :.(I_(0))/3=I_(0)cos^(2) theta` `cos theta=+-1/(sqrt(3))`Hence`theta=54.73^(@)` |
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