1.

Two polaroids are placed in the path of unpolarised light beam of intensity I_(0) such that no light is emitted from the second polarisation. If a third polaroid whose polarisation axis makes an angle theta with that of the first polaroid is placed between the polaroids, then intensity of light emerging from the last polaroid is

Answer»

`((I_(0))/(8))sin^(2) 2theta`
`((I_(0))/(4))sin^(2) 2theta`
`((I_(0))/(2))cos^(2) theta`
`I_(0)cos^(2)theta`

Solution :When unpolarised light passes through first polarister, it BECOMES polarised and its intensity becomes HALF.
`therefore` After first polarister, intensity `I_(0)=I_(0)//2`
After second polariser, intensity `I_(2)=(I_(0))/(2) cos^(2) theta`
(MALUS law)
After third polariser, intensity
`I_(3)=(I_(0))/(2) cos^(2) theta cos^(2) (90^(@)-theta)`
(because this is at `90^(@)` angle from first polariser)
`rArr I_(3) =(I_(0))/(2) cos^(2) theta sin^(2) theta=(I_(0))/(8)(2 sin theta cos theta)^(2)=(I_(0))/(8) sin^(2) 2 theta`


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