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Two projectile are projected simultaneously from a point on the ground "O" and an elevated position "A" respectively as shown in the figure. If collision occurs at the point of return of two projectiles on the horizontal surface, then find the height of "A" above the ground and the angle at which the projectile "O" at the ground should be projected. |
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Answer» SOLUTION :There is no initial separation between two projectile is x-direction. For collision to occur, the relative motion in x-direction should be zero. In other words, the component velocities in x-direction should be equal to that two projetiles cover equal horizontal distance at any given time. HENCE, `u_(Ox)=u(Ax)` `impliesu_0costheta=u_A` `impliescostheta=(u_A)/(u_0)=5/(10)=1/2=cos60^(@)` `impliestheta=60^(@)` We should ensure that collision does occur at the point of RETURN. It means that by the time projectiles travel horizontal distances required, they should also cover vertical distances so that both projectile areat "C" at the same time. In the nutshell, their timesof flight should be equal. For projectile from "O" `T=(2u_Osintheta)/(g)` For projectile from "A", `T=sqrt((2H)/(g))` For projectile from " A" `T=(2u_0sintheta)/g=sqrt(((2H)/(g)))` Squaring both sides and putting values, `impliesH=(4u_(O)^(2)sin^2theta)/(2g)` `impliesH=(4xx10^2sin260^(@))/(2XX10)` `H=20((sqrt3)/(2))^2=15m` We have deliberately worked out this problem taking advantage of the fact that projectiles are colliding at the end of their flights and hence their times of flight should be equal. We can, however, proceed to analyze in typical manner, using CONCEPT of relative velocity. The initial separation between two projectiles in the vertical direction is "H". This separation is covered with the component of relative in vertical direction. `impliesv_(OAy)=u_(Oy)-u_(Ay)=u_Bsin60^(@)-0=10xx(sqrt3)/2` `=5sqrt3m//s` Now, time of flight of projectile from ground is : `T=(2u_0sintheta)/(g)=(2xx10xxsin60^(@))/(10)=sqrt3` Hence, the vertical displacement of projectile from "A" before collision is : `impliesH=v_(OAy)XT=5sqrt3xsqrt3=15m//s` |
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