1.

Two projectiles A and B are thrown from the samepoint with velocities v and v/2 respectively. If B is thrown at an angle 45° with horizontal, what is the inclination of A when their ranges are the same ?

Answer»

`sin^(-1)(1/4)`
`1/2sin^(-1)(1/4)`
`2sin^(-1)(1/4)`
`1/2sin^(-1)(1/8)`

Solution :RANGE of B `R_(2)=(v/2)^(2)(sin90^@)/G=v^(2)/(4G)`
and range of A, `R_(1)=(v^(2)sin2theta)/g`
As `R_(1)=R_(2) :. (v^(2)sin2theta)/g=v^(2)/(4)`
`sin2theta=1/4implies 2theta=sin^(-1)(1/4)`
`theta=1/2in^(-1)(1/4)`


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