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Two projectiles are thrown from the same point simultaneously with same velocity 10 ms^(-1) . One goes straight vertically while other at 60° with the vertical. What will be the distance of separation between the two after 1 second of their throw ? |
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Answer» 20m vertical velocity =`10 cos 60° = 5 ms^(-1)` Horizontal SEPARATION `Deltax = 5sqrt(3) xx 1` `=5sqrt(3)m` Vertical seperation = `h_(1)-h_(2)` `Deltay=(10t-1/2g^(2)t)-[5t-1/2g^(2)t]` `=10xx1-5xx1)=5m` `:.` displacement `|r|=sqrt((5sqrt(3))^(2)+5^(2))` |
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