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Two radiations with photon energies 0.9 eV and 3.3 eV respectively are falling on a metallic surface successively. If the work function of the metal is 0.6 eV, then the ratio of maximum speeds of emitted electrons will be………………… |
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Answer» `1 : 4` `v_(2_(max)) = sqrt((2(h upsilon - phi))/(m)) = sqrt((2(3.3-0.6))/(m)) = sqrt((2(2.7))/(m))` `(v_(1_(max)))/(v_(2_(max)))=sqrt((2(0.3))/(m))XX sqrt((m)/(2(2.7)))=sqrt((0.3)/(2.7))=(1)/(3)` `(v_(1) : v_(2))_(max) = 1 : 3` |
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