1.

Two radiations with photon energies 0.9 eV and 3.3eV respectively are falling on a metallic surface successively. If the work function of the metal is 0.6 eV , then the ration of maximum speeds of emitted electrons will be

Answer»

`1 : 4`
`1:3`
`1:1`
`1: 9`

SOLUTION : `v_(1_("MAX"))=SQRT((2(hv-phi))/(m))= sqrt((2(0.9-0.6))/(m)) =sqrt((2(0.3))/(m))`
`v_(2_"max")=sqrt(((hv-phi))/(m)) = sqrt((2(3.3-0.6))/(m)) = sqrt((2(2.7))/(m))`
`v_(1_(max)) = sqrt((2(0.3))/(m)) xx sqrt((m)/(2.7)) = sqrt(0.3 / 2.7 )= 1/3`
`(v_1 : v_2 ) _(max) = 1:3`


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