Saved Bookmarks
| 1. |
Two relativistic particles move at right angles to each other in a laboratory frame of reference, one with the velocity v_1 and the other with the velocity v_2. Find their relative velocity. |
|
Answer» Solution :The approach VELOCITY is defined by `vecV_(approach)=(dvecr_1)/(dt)-(dvecr_2)/(dt)=V_1-vecV_2` in the laboratory FRAME. So `V_(approach)=sqrt(v_1^2+v_2^2)` On the other hand, the RELATIVE velocity can be obtained by USING the velocity addition formula and has the componets `[-v_1, v_2sqrt(1-(v_1^2/c^2))]` so `V_r=sqrt(v_1^2+v_2^2-(v_1v_2^2)/(c^2))` |
|