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InterviewSolution
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Two resistors are connected in series across `5V` rms source of alternating potentail. The potential difference across `6 Omega` resistor is `3 V_(m)`. If `R` is replaced by a pure inductor `L` of such magnitude that current remains same, then the potential difference across `L` is |
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Answer» Correct Answer - 4 Initially `i=(2)/(R )=(3)/(6) therefore R=4Omega , i=(1)/(2)A` Whebn `R` is replaced by `L,i` does not change `therefore (1)/(2)=(5)/(sqrt(4^(2)+X_(L)^(2)))," " therefore X_(L)=8Omega` `therefore V_(L)=iX_(L)=(1)/(2)xx8=4V` |
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