InterviewSolution
Saved Bookmarks
| 1. |
Two resistors are connected in series with 5V battery of negligible internal resistance. A current of 2A flows through each resistor. If they are connected in parallel with the same battery of current of 25/3AA flows through combination. Calculate the value of each resistance. |
Answer» SOLUTION : `I_g=(IS)/(G+S)`….(I) `I_gG=(I-I_g)S` or `S=(I_gG)/(I-I_g) ""I_gG=IS-I_gS` `thereforeI_g=(IS)/(G+S)` `I_gG+I_gS=IS , "" (G+S)I_g=IS` from EQUATION (1) `I_g PROP I` Since S and G are CONSTANTS, the scale can be graduated to give the main CURRENT directly. |
|