Two resistors of resistances 200 kOmega and 1 Momega respectively form a potential divider with outer junctions maintained at potentials of +3 V and -15 V. Then, the potential at the junction between the resistors is

Two resistors of resistances 200 kOmega and 1 Momega respectively form

1.	Two resistors of resistances 200 kOmega and 1 Momega respectively form a potential divider with outer junctions maintained at potentials of +3 V and -15 V. Then, the potential at the junction between the resistors is
Answer» `0 V` `+1 V` `-12 V` `+12 V` Solution :Potential difference across `1MOmega` resistor is `V_(P)-V_(B)=(18Vxx1xx10^(6)Omega)/((0.2+1)xx10^(6)Omega)` `=(18Vxx1xx10^(6)Omega)/(1.2xx10^(6)Omega)=15V` `V_(B)=-15V` (Given) `therefore V_(P)-V_(B)=15V` or `V_(P)=15V+V_(B)=15V-15V=0V` Potential difference across `20kOmega` resistor is `V_(A)-V_(P)=(18Vxx0.2xx10^(6)Omega)/((0.2xx1)xx10^(6)Omega)=(18Vxx0.2xx10^(6)Omega)/(1.2xx10^(6)Omega)=3V` `V_(A)=+3V` (Given) `therefore V_(A)-V_(P)=3VorV_(P)=V_(A)-3V=+3V-3V=0V`

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Two resistors of resistances 200 kOmega and 1 Momega respectively form a potential divider with outer junctions maintained at potentials of +3 V and -15 V. Then, the potential at the junction between the resistors is

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