Two resistors, X and R, are connected in the left gap and the right gap of a metre bridge, and the null point in obtained at 20 cm from the left end. With X + 24 Omega in the left gap and the same resistance R in the right gap, the null point is at the centre of the wire. Then, X is equal to

Two resistors, X and R, are connected in the left gap and the right ga

1.	Two resistors, X and R, are connected in the left gap and the right gap of a metre bridge, and the null point in obtained at 20 cm from the left end. With X + 24 Omega in the left gap and the same resistance R in the right gap, the null point is at the centre of the wire. Then, X is equal to
Answer» `4.8 Omega` `6 Omega` `8 Omega` `12 Omega` Solution :`(X)/(R)=(20)/(80)=(1)/(4), (X+24)/(R)=1. therefore (X+24)/(X)=4`

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Two resistors, X and R, are connected in the left gap and the right gap of a metre bridge, and the null point in obtained at 20 cm from the left end. With X + 24 Omega in the left gap and the same resistance R in the right gap, the null point is at the centre of the wire. Then, X is equal to

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