InterviewSolution
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InterviewSolution
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Two rigid bodies `A` and `B` rotate with angular momenta `L_(A)` and `L_(B)` respectively. The moments of inertia of `A` and `B` about the axes of rotation are `I_(A)` and `I_(B)` respectively. If `I_(A)=I_(B)//4` and `L_(A)=5L_(B)`, then the ratio of rotational kinetic energy `K_(A)` of `A` to the rotational kinetic energy `K_(B)` of `B` is given byA. `(K_(A))/(K_(B))=25/4`B. `(K_(A))/(K_(B))=5/4`C. `(K_(A))/(K_(B))=1/4`D. `(K_(A))/(K_(B))=100` |
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Answer» Correct Answer - D `K_(A)=(L_(A)^(2))/(2l_(A))=(25L_(B)^(2))/(2l_(B))` `K+B=(L_(B)^(2))/(2l_(B))` Now, `(K_(A))/(K_(B))=25xx4=100` |
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