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Two Rods of same cross sectional area and same length but different thermal conductivity K_(1) and K_(2) are first connected in series and then connected in parallel between same temperature difference in both cases Then the ratio of rates of heat flow in both cases is. |
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Answer» `(4k_(1)k_(2))/((k_(1)+k_(2))^(2))` `(v_("PARTICLE"))_("max")=Aomega=(2piAV)/(lambda)` WAVE speed `=v=(omega)/(k)` |
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