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Two rods one is semi circular of thermal conductivity `K_(1)` and otheir is straight of thermal conductivity `K_(2)` and of same cross sectional area are joined as shown in the The points `A` and `B` are maintained at same temperature difference. If rate of flow of heat is same in two rods then `K_(1)//K_(2)` is .A. `2:pi`B. `1:2`C. `pi:2`D. `3:2` |
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Answer» Correct Answer - C `((Q)/(t))_("semicircularrod")=((Q)/(t))_("straightrod")` `(K_(1)A(Deltatheta))/(pir)=(K_(2)A(Deltatheta))/(2r)` r =` radius of semi circle . |
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