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Two samples `1` and `2` are initially kept in the same state. The sample `1` is expanded through an isothermal process where as sample `2` through an adiabatic process upto the same final volume. The final temperature in process `1` and `2` are `T_(1)` and `T_(2)` respectively, thenA. `T_(1) gt T_(2)`B. `T_(1) = T_(2)`C. `T_(1) lt T_(2)`D. The relation between `T_(1)` and `T_(2)` cannot be deduced. |
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Answer» Correct Answer - A For adiabatic `TV^(gamma -1) (gamma gt 1) ……….(i)` For isothermla `T =` const ……..(ii) From (i) and (ii) (i), `T_(2) lt T_(1)` |
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