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Two satellite A and B, ratio of masses `3:1` are in circular orbits of radii `r and 4r`. Then ratio mechanical energy of A and B isA. `1:3`B. `3:1`C. `3:4`D. `12:1` |
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Answer» Correct Answer - D Energy of satellite is given by `E=-(GMm)/(2r)or E prop (m)/(r)` `rArr (E_(A))/(E_(B))=(m_(A))/(m_(B))xx(r_(B))/(r_(A))=(3)/(1)xx(4r)/(r)" "{because (m_(A))/(m_(B))=(3)/(1),(r_(B))/(r_(A))=(4r)/(r)}` `rArr (E_(A))/(E_(B))=(12)/(1)`. |
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