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Two satellites A and B revolve round a planet in coplanar orbits in the same direction, rheir periods are 1 hour and 8 hours respectively. The orbital radius of A is 10^(4) km the speed of B relative to A when they are closest is : |
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Answer» `10^(4)pi KM//h` `therefore v_(1)=(2pi r_(1))/(T_(1))=(2pi XX 10^(4))/(1)km//hr` As`r_(1)=10^(4)km`  By Kepler.s LAW `(r_(2))/(r_(1))=((T_(2))/(T_(1)))^(2//3)=((8)/(1))^(2//3)` or `r_(2)=4xx10^(4)km` `v_(2)=(2pi r_(2))/(T_(2))=(2pi xx4xx10^(4))/(8)` `=pi xx 10^(4) km//hr`. Correct choice is (a). |
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