1.

Two sides of a rhombus lying in the first quadrant are given by 3x-4y=0 and 12x-5y=0. The length of the longer diagonal is 12. If the equations of other two sides are 3x-4y+180/sqrta=0 and 12x-5y=468/sqrta " then " (a-40)/10=

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ANSWER :9


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