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Two sides of the quadrilateral are in the ratio of 2:3 find them |
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Answer» Answer: Answer Let the ANGLES of the quadrilateral in DEGREES be =2a,3a,4a and a Since the sum of angles of a quadrilateral =360 o , 2a+3a+4a+a=360 o
10a=360 o
a=36 So, the angles of the quadrilateral are =2a=72 o ,3a=108 o ,4a=144 o and a=36 Suppose ∠A=72 o and ∠B=108 o
Sum of ∠A and ∠B=72 o +108 o =180 o
This means, AB is a transversal to the parallel SIDES AD and BC as the sum of interior angles on the same side of transversal is 180 o
Hence, AD∥BC and ABCD is a trapezium |
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