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Two similarly and equally charged idential metal spheres A and B repel each other with a force of2 xx 10 ^(-5)) N.A third identical uncharged sphere C is touched with A and then , placed at the mid - point between A and B. Calculate the net electric force on C. |
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Answer» Solution :Let charges on A and B be Q each R be the distance between them. Then as shown in we have. ` F= ( 1)/(4pi in _0) .(q^(2))/( r^(2)) =2 xx10 ^(-5)N. ` On touching C with A , charge on A as well as C will be `(q)/(2) `. Now as shown in net force on C is ` "" F_C =|oversetto (F_(CA)) +oversetto (F_(CB))| =oversetto (F_(CB)) -oversetto (F_(CA)) =(1)/(4pi in _0) .(((q)/(2)) ((q)/(2)))/( ((r)/(2)) ) ` ` =(1)/(4piin _0) [(2q^(2))/(r^(2)) -(q^(2))/(r^(2)) ]=(1)/(4 pi in _0) =2 xx 10 ^(-5) N `along CA. ` (##U_LIK_SP_PHY_XII_C01_E09_003_S01.png" WIDTH="80%"> |
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