InterviewSolution
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InterviewSolution
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Two simple harmonic are represented by the equation `y_(1)=0.1 sin (100pi+(pi)/3) and y_(2)=0.1 cos pit`. The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is.A. (a) `(pi)/3`B. (b) (-pi)/6`C. (c ) `(pi)/6`D. (d) (-pi)/3` |
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Answer» Correct Answer - B (b) `v_(1)=(dy_(1))/(dt)=0.1xx100pi cos(100pi+(pi)/3)` `v_(2)=(dy_(2)/(dt)=-0.1pi sint=0.1 cos(pit+(pi)/2)` :. Phase diff=phi_(1)=(pi)/3=(pi)/2=(2pi-3pi)/6=-(pi)6`. |
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