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Two simple harmonic motions are given by `y_(1) = a sin [((pi)/(2))t + phi]` and `y_(2) = b sin [((2pi)/( 3))t + phi]`. The phase difference between these after `1 s` isA. zeroB. `pi//2`C. `pi//4`D. `pi//6` |
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Answer» Correct Answer - D At `t = 1 s` `phi_(1) = (pi)/(2) + phi` and `phi_(2) = (2pi)/(3) + phi` `:. Delta phi = phi_(2) - phi_(1) = (pi)/(6)` |
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