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Two simple pendulum of lengths 16I and I are in phase at the mean position at a certain time.IF T is the time period of shorter pendulum. The maximum time after which they will be again in phase. |
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Answer» `1/3T` `Talpha sqrt(l)` The PENDULUM having time period makes one oscillation LESS than the other. `(T_1-1)/(T_1)=sqrt(l)/(16l)=1/4` `implies (T_1-1)/(T_1)=1/4` `implies1-(1)/T_1=1/4` `T=4//4` Theywill be again in PHASE after`4/3T`, |
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