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Two simple pendulums A and B are made to oscillate simultaneously and it is found that A completes 10 oscillations in 20 sand B completes 8 oscillations in 10 s. The ratio of the lengths of A and B is |
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Answer» `(8)/(5)` For PENDULUM A, `T_(A) = 2pi sqrt((I_(A))/(g))` `(20)/(10)=2pi sqrt((I_(A))/(g))` For pendulum B, `T_(B)=2pi sqrt((I_(B))/(g))` `(10)/(8)=2pi sqrt((I_(B))/(g))` Dividing Eq. (i) by Eq. (II), we GET `(I_(A))/(I_(B))=((160)/(100))^(2)` `(I_(A))/(I_(B))=(64)/(25)` |
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