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Two simple pendulums, having periods of `2s` and `3s` respectively, pass through the mean position simulaneously at a particular instant. They may be in phase after an interval of:A. `5s`B. `6s`C. `1s`D. none of these above |
Answer» Correct Answer - B `omega_(1) = (2pi)/(2) = pi` and `omega_(2) = ((2pi)/(3))` They will be in phase if `(omega_(t) - omega_(2)) t = 0, 2pi, 4pi`….. `t = (2pi)/((omega_(1) - omega_(2))) = (2pi)/(pi - (2pi)/(3)) = 6` sec |
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