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InterviewSolution
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Two sinusoidal voltage of the same frequency are shown in the diagram. What is the frequency, and the phase relationship between the voltage? Frequency in `Hz` phase lead of `N` over `M` in radiusA. Frequency/Hz =0.4, phase lead of N over M in rad `s^(-1)`= `-(pi)/(4)`B. Frequency/Hz =2.5, phase lead of N over M in rad `s^(-1)`= `-(pi)/(2)`C. Frequency/Hz =2.5, phase lead of N over M in rad `s^(-1)`= `2(pi)/(2)`D. Frequency/Hz =2.5, phase lead of N over M in rad `s^(-1)`= `-(pi)/(4)` |
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Answer» Correct Answer - B the period of sinusoidal voltage , T=0.4s. `f=1/T=1/(0.4)=2.5Hz` N lags M by 0.1 s which is equivalent to `((0.1)/(0.4)) 2 pi or (pi)/(2) rad`. Thus, the lead of N over M is `-(pi)/(2) rad`. |
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