Two slabs A and B, each though similar, in all other respects, have different materials. They are placed one above the other in perfect contact and a steady difference of temperature of 36^(@)C is maintained across the combination. If the thermal conductivity ofA is twice that of B, what is the temperature of interface ?

Two slabs A and B, each though similar, in all other respects, have di

1.	Two slabs A and B, each though similar, in all other respects, have different materials. They are placed one above the other in perfect contact and a steady difference of temperature of 36^(@)C is maintained across the combination. If the thermal conductivity ofA is twice that of B, what is the temperature of interface ?
Answer» `16^(@)C` `12^(@)C` `28^(@)C` `24^(@)C`. SOLUTION :In steady state, rate of flow of HEAT is same `H_(1)=H_(2)`. `(k_(1)ADeltatheta_(1))/(d)=(k_(2)ADeltatheta_(2))/(d)` `(Deltatheta_(1))/(Deltatheta_(2))=(k_(2))/(k_(1))=1/2` `Deltatheta_(2)=2Deltatheta_(1)`. Also `Deltatheta_(1)+Deltatheta_(2)=36^(@)C` `:.""3Deltatheta_(1)=36^(@)C` `Deltatheta_(1)=12^(@)C` `rArr36-T=12rArrT=24^(@)C` Thus correct choice is (d).

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