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Two slits 0.3mm apart are illuminated by light of wavelength 4500Å. The screen is placed at 1m distance from the slits. Find the separation between the second bright fringe on both sides of the central maximum. Data : d=0.3mm=0.3xx10^(-3)m, lambda=4500Å=4.5xx10^(-7)m, D=1m, n=2, 2x=?

Answer»

SOLUTION :`2x=2(D)/(d)nlambda`
`=(2xx1xx2xx4.5xx10^(-7))/(0.3xx10^(-3))`
`:.2x=6xx10^(-3)m` (or) `6MM`


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